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A new proof of the theorem that every integral rational algebraic function of one variable can be re

OdradekOdradek
edited 2014-04-11 00:00:11 in General
Who knows what this means? Nobody that's who.

Comments

  • Obā-sanObā-san

  • OdradekOdradek
    My dreams exceed my real life
    user posted image
  • OdradekOdradek
    My dreams exceed my real life
    replaces dicks with status=all conversations about Gauss
  • OdradekOdradek
    My dreams exceed my real life
    DYNAMIC ILLUSION OF MEANING
  • OdradekOdradek
    My dreams exceed my real life
    Why GAUSS and not Michael FARADAY
  • OdradekOdradek
    My dreams exceed my real life
    Sacredness that's why
  • Previous CalicaPrevious Calica
    (flower path)
    Odradek said:

    Who knows what this means? Nobody that's who.

    looks like it's saying something about ratios of polynomials but it was cut off
  • KlinotaxisKlinotaxis
    edited 2014-04-11 02:31:13
    kill living beings
    Demonstratio nova theorematis omnem functionem algebraicam rationalem integram unius variabilis in factores reales primi vel secundi gradus resolvi posse, HTH

    kind of surprised it wasn't 'represented', such is modernity!
  • Previous CalicaPrevious Calica
    edited 2014-04-11 05:26:47
    (flower path)
    oh it's the fundamental theorem of algebra, written confusingly(at the end, to avoid mentioning complex numbers)
  • Previous CalicaPrevious Calica
    (flower path)
    so the enemy gives you a polynomial, I can find a complex number, plug that number into the polynomial and get zero.
  • AnonusAnonus
    I've learned to tolerate drama...except on the boat
    this is the best thread ever
  • BeeBee
    So e^x is walking through the forest one day, and he comes across a bridge.

    "BEWARE!" says a voice from under the bridge.  "This is the bridge of differentiation!  All ye who cross it shall be differentiated!"

    e^x says "bitch I don't care.  I'm e^x, my derivative is myself!"

    So e^x walks across the bridge...

    ...and gets differentiated with respect to y.
  • OdradekOdradek
    My dreams exceed my real life
    Bee said:

    So e^x is walking through the forest one day, and he comes across a bridge.

    "BEWARE!" says a voice from under the bridge.  "This is the bridge of differentiation!  All ye who cross it shall be differentiated!"

    e^x says "bitch I don't care.  I'm e^x, my derivative is myself!"

    So e^x walks across the bridge...

    ...and gets differentiated with respect to y.

    MOONTALK
  • glennmagusharveyglennmagusharvey
    edited 2014-04-12 00:40:40
    no, that's from the math dimension, as opposed to the language dimension.  There is a language dimension, a math dimension, and a music and sounds dimension.  and probably a smells and tastes dimension.

    moontalk is japanese language from the language dimension.
  • BeeBee
    What's an anagram of "Banach-Tarski"?

    "Banach-Tarski Banach-Tarski"
  • TachyonTachyon
    imagei will watch the heck outta this pumpkin patch
    i hadn't heard that one before.

    very silly. :)
  • Previous CalicaPrevious Calica
    (flower path)
    Bee said:

    What's an anagram of "Banach-Tarski"?

    "Banach-Tarski Banach-Tarski"

    i once went to a forum that had that as a word filter
  • BeeBee
    Did it recursively screw with blockquotes?
  • Previous CalicaPrevious Calica
    edited 2014-04-12 14:21:57
    (flower path)
    Bee said:

    Did it recursively screw with blockquotes?

    Yep.  That's pretty much its raison d'etre.  Because Batman → Batman, the Caped Crusader just wasn't doing it enough.
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