its 2:14 am

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  • did I already make a thread identical to this, I forget
  • FUCK/19415.968 = 32

    solve for FUCK
  • Ah, good memories of late-night statics and dynamics homework.  That shit was all super long-form problems.
  • edited 2017-09-17 06:30:30
    1. A journalist throws a shoe at a head of state.  The shoe leaves the journalist's hand at height h_j and with velocity v_0 with nonzero horizontal and vertical components.  If the shoe hits the face of the head of state at height h_hos when coming down, write an expression for the distance between the journalist and the head of state.

    2. If the head of state dodges the shoe by ducking, and has face that is approximately circular with radius r_f, which the shoe would hit squarely on the nose if the head of state did not duck, and can duck at a solely-downward velocity of v_d, calculate the time at which the head of state would need to begin ducking for the shoe to just barely graze his hair.
  • Sup bitches, witches, Haters, and trolls.
    let G be a group with a special(determinant 1) representation over a two-dimensional space V

    now consider tensoring a representation with V.  the dimension will be twice as big, but it'll be a sum of other representations.  you can make a graph where U is connected to W if U tensor V contains a copy of W, because U is the same as U dual and the character math will always work out very nicely

    in the weirdest case, 2A_5, the graph is: you take a node in the center, attach one node to the center, attach a chain of two nodes to the center, and attach a chain of five nodes to the center.  the one way furthest out is the trivial rep, and the one right next to it is V.

    in principle you can get the whole character table from this, but i'm only going to do dimensions.  2 is twice as big as 1, 2*2 is 1+3, 3*2 is 2+4, so on until you reach 6 at the center.  the one poking out has to be 3, and then you subtract 3 and 5 from 2*6 to get 4.  then the last one has to be 2.  cool.
  • I'm too asleep to understand that right now but cool
  • Sup bitches, witches, Haters, and trolls.
    https://en.wikipedia.org/wiki/McKay_graph

    that might be actually understandable to someone who is willing to put in the time to understand rep theory
  • edited 2017-09-17 07:38:55
    Kodaka: "Why are you guys so early?  We've still got 10 minutes before 1."
    Yozora: "I wasn't first.  I got here 5 minutes after Rika did."
    Yukimura: "Well, I only arrived 20 minutes before you did because I'm your sidekick."
    Rika: "Rika managed to beat Sena to our meeting place by 15 minutes."
    Sena: "But I was still here 15 minutes before Yukimura."
    Kodaka: "Why are you guys talking like you're in the middle of some math word problem?"
    Kodaka: "Okay, try to figure out who got here, what time, based on what they all just said."
    Kobato: "Huh?"
    Kodaka: "Come on, it'll be fun for you!  Now we arrived at exactly 12:50.  You have until we get to the karaoke place to answer."
    Kobato: "Uh...what?!"
    Kobato: "Um......ku ku ku!  You forget all I need to do is access the Akashic Records and solving a problem like this one shall be a breeze!  Watch and learn, mortal.  I'll have the answers for you in no time, probably."
    Kodaka: "Why do you have to use the powers of darkness on everything?"
  • it is three hours later now.  what time is it now?
  • image Wee yea erra chs hymmnos mea.
    14:57
  • but is the fear gone?
  • BeeBee
    edited 2017-09-17 17:59:33
    Your baby sister is about to drool into your brand new $1000 motherboard.  Her mouth is six inches above the surface.  The drool is highly viscous and accelerates downward at 0.3g.  You are standing at rest in the doorway, 15 feet away.  Assuming your hand is infinitely thin, how much time do you have to catch the drool, and how quickly must you accelerate to do so?

    *actual question on my AP physics exam*
  • kill living beings
    inches? feet? what is this shit
  • assuming your hand is infinitely thin
  • image Wee yea erra chs hymmnos mea.
    Inverse yaoi hands.
  • Bee said:

    Your baby sister is about to drool into your brand new $1000 motherboard.  Her mouth is six inches above the surface.  The drool is highly viscous and accelerates downward at 0.3g.  You are standing at rest in the doorway, 15 feet away.  Assuming your hand is infinitely thin, how much time do you have to catch the drool, and how quickly must you accelerate to do so?


    *actual question on my AP physics exam*
    this question was beamed in from another dimension
  • image Wee yea erra chs hymmnos mea.
    who spends that much on their mobo anyway
  • BeeBee
    edited 2017-09-17 19:58:14
    Jane said:

    Bee said:

    Your baby sister is about to drool into your brand new $1000 motherboard.  Her mouth is six inches above the surface.  The drool is highly viscous and accelerates downward at 0.3g.  You are standing at rest in the doorway, 15 feet away.  Assuming your hand is infinitely thin, how much time do you have to catch the drool, and how quickly must you accelerate to do so?


    *actual question on my AP physics exam*
    this question was beamed in from another dimension
    If you want to talk about beamed in from another dimension, here's another from one of our homework assignments.

    The Star Trek away team beams down onto a planet, and accidentally finds themselves on an alien superhighway!  Zonx, a three-eyed alien wearing glasses (his friends call him Six-Eyes), is driving at one km per second.  He sees the away team on the road from 2 km away and stomps on the brakes, decelerating at a rate of 100 m/s^2.

    The ranking officers all jump out of the way of course, but does Zonx stop in time for the redshirts?  Calculate either the distance he stops from them, or the speed at which he hits them.

    (spoilers, they die)
  • Touch the cow. Do it now.
    redshirts die? that question is a gimme.
  • Of course, but you also had to give the exact speed for maximum lulz.
  • edited 2017-09-17 23:49:49

    -50x^2 + 1000x - 2000 = 0. Solve for x. That seems about right.

    x^2 - 20x + 40 = 0

    b^2 - 4ac = 400 - 4*1*40 = 400 - 160 = 240 > 0; real solutions available, rational solutions not available

    rest of problem to be outsourced to a high school student
  • edited 2017-09-18 00:20:11
    Sup bitches, witches, Haters, and trolls.
    x^2-20x+40=0, (x-10)^2-60=0, x=10-sqrt(60), sqrt(60) is about 7.7 probably, so x is about 2.3, 1000-330=770 plus or minus some meters per second

    edit: i somehow thought sqrt(60) was between 6 and 7 even though i did an in-my-head interpolation calc between 49 and 64.  derp.
  • BeeBee
    edited 2017-09-18 00:03:18
    v^2 = v0^2 + 2ad is actually the equation you're looking for.  It's typically more useful than a straight quadratic when you expect intermediate speeds to be relevant.

    First you assume v = 0 for a full stop, then find the distance to do it is greater than the given distance.  Then you plug in the given distance instead and solve for v.

    v^2 = (1000 m/s)^2 + 2 * (-100 m/s^2) * (2000 m)
     = (1000000 - 400000) m^2/s^2

    v = sqt(600000) = about 775 m/s
  • Sup bitches, witches, Haters, and trolls.
    i hadn't used that particular equation since high school physics
  • edited 2017-09-18 00:36:59
    I took first year physics in undergrad but honestly I fell asleep before I finished reading that question

    word problems can eat a dick imo
  • I remember there are four handy two-dimensional projectile motion equations in physics except I've forgotten what they are, aside from the fact that one of them is basically the derivative of another one.
  • Touch the cow. Do it now.
    as a writer, I know nothing of math
  • as a writer, I know nothing of math

    what is the volume of milk that can be contained a two spheres both with radius r?
  • Touch the cow. Do it now.
    look, the last time I did the math, I ended up with an Atari Jaguar.

    I learned my lesson
  • moves everyone's beacons under moon and star
  • vtkvtk
    embrace the confusion
    Find the volume of the golden earring with inner diameter 66mm and outer diameter 70mm
  • vtk said:

    Find the volume of the golden earring with inner diameter 66mm and outer diameter 70mm

    wait i know you can do this with calculus but can you do with just algebra?
  • BeeBee
    edited 2017-09-18 04:43:29
    Calica said:

    i hadn't used that particular equation since high school physics

    This was high school physics (albeit AP), so :P

    Of course with my brief foray into game design hammering really hard on kinematics was pretty important.
  • vtkvtk
    embrace the confusion

    vtk said:

    Find the volume of the golden earring with inner diameter 66mm and outer diameter 70mm

    wait i know you can do this with calculus but can you do with just algebra?
    You can if someone gives you the torus volume formula or if you derive said formula by taking an intuitive leap that probably requires calculus to prove, but the same is true for many other simple geometric figures with simple volume formulas.
  • edited 2017-09-19 05:14:29
    let x>=0 and y>=0

    if x+y>=0 then go to other thread
  • vtk said:

    vtk said:

    Find the volume of the golden earring with inner diameter 66mm and outer diameter 70mm

    wait i know you can do this with calculus but can you do with just algebra?
    You can if someone gives you the torus volume formula or if you derive said formula by taking an intuitive leap that probably requires calculus to prove, but the same is true for many other simple geometric figures with simple volume formulas.
    Alternatively drop the earring in water and measure the displaced volume.  /engineeranswer
  • When Archimedes' circles were disturbed, he knew damn well he had been cheated
  • vtkvtk
    embrace the confusion
    So yeah I'm pretty sure the volume of a torus is V = 2π2rarb2 so in my problem ra = 68mm and rb = 2mm so V ~= 5369.06mm3 = 5.36906mL. I intuited that, and am pretty sure the calculus would check out.

    Now to check Wikipedia for the correct volume formula… yeah, just slightly different parameter names.
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